Math, asked by Ravindar6577, 10 months ago

y = sin(tan-1 e^{-1}) dy/dx ज्ञात कीजिए

Answers

Answered by amitnrw
0

dy/dx   =   -Cos (Tan⁻¹ e⁻ˣ) e⁻ˣ/(1 + e⁻²ˣ)  यदि y = Sin ( Tan⁻¹ e⁻ˣ)

Step-by-step explanation:

dy/dx ज्ञात कीजिए

y = Sin ( Tan⁻¹ e⁻ˣ)

dy/dx  =  Cos (Tan⁻¹ e⁻ˣ) *  d  (Tan⁻¹ e⁻ˣ)/dx

d( Tan⁻¹x)  = 1/(1 + x²)

dy/dx   =    Cos (Tan⁻¹ e⁻ˣ) * (1/(1 + (e⁻ˣ)²) ) * d( e⁻ˣ)/dx

d( e⁻ˣ)/dx = - e⁻ˣ

dy/dx   =    Cos (Tan⁻¹ e⁻ˣ) * (1/(1 + (e⁻ˣ)²) ) * (-e⁻ˣ)

=> dy/dx   =   -Cos (Tan⁻¹ e⁻ˣ) e⁻ˣ/(1 + e⁻²ˣ)

और अधिक जानें :

sin(x²+5)"

brainly.in/question/15286193

sin (ax+b) फलन का अवकलन कीजिए

brainly.in/question/15286166

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