Math, asked by mishthi3176, 8 months ago

sin 20/cos 70+sin 20*sec 70+sin^230

Answers

Answered by Anonymous
4

Answer:

sin(90°-α) = cosα

cos(90°-α) = sinα

so,

cos70°/sin20° + cos59°/sin31° -8 sin²30°

=[cos(90°-20)]/sin20° + [cos(90°-31°)]/sin31° - 8×(1/2)²

=sin20°/sin20° + sin31°/sin31° - 2

= 1+1- 2

= 0

hope it helps you...

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