sin^2x diffrentiation
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f(g(x))' = f'(g(x))g'(x). f'(x) = cos(2x) and g'(x) = 2 and by the Chain Rule we get: h'(x) = 2cos(2x). The differentiation, or the derivative of sin(2x) is therefore 2cos(2x)
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dibakartaj:
it is not sin 2x it is sin^2x
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