sin(4x)-sin(3x)+sin(2x)-sin(x)=0 hayar los valores de x
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In this way, using the sum-to-product formula for sinus and cosine:
sin
α
+
sin
β
=
2
sin
(
α
+
β
2
)
cos
(
α
−
β
2
)
cos
α
+
cos
β
=
2
cos
(
α
+
β
2
)
cos
(
α
−
β
2
)
.
So:
(
sin
4
x
+
sin
x
)
+
(
sin
3
x
+
sin
2
x
)
=
0
⇒
2
sin
(
4
x
+
x
2
)
cos
(
4
x
−
x
2
)
+
+
2
sin
(
3
x
+
2
x
2
)
cos
(
3
x
−
2
x
2
)
=
0
2
sin
(
5
2
x
)
cos
(
3
2
x
)
+
2
sin
(
5
2
x
)
cos
(
1
2
x
)
=
0
2
sin
(
5
2
x
)
[
cos
(
3
2
x
)
+
cos
(
1
2
x
)
]
=
0
2
sin
(
5
2
x
)
2
cos
(
3
2
x
+
1
2
x
2
)
cos
(
3
2
x
−
1
2
x
2
)
=
0
4
sin
(
5
2
x
)
cos
x
cos
(
x
2
)
=
0
.
Then:
sin
(
5
2
x
)
=
0
⇒
5
2
x
=
k
π
⇒
x
=
2
5
k
π
,
cos
x
=
0
⇒
x
=
π
2
+
k
π
,
cos
(
x
2
)
=
0
⇒
x
2
=
π
2
+
k
π
⇒
x
=
π
+
2
k
π
.
Answered by
0
I don’t knw can u answer my but
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