Math, asked by aaron200737, 3 months ago

sin 6theta-sin 2theta

Answers

Answered by Anonymous

3

Answer:sin6θ+sin2θ=0

2sin

2

6θ+2θ

cos

2

6θ−2θ

=0

⇒2sin4θcos2θ=0

⇒sin4θcos2θ=0

sin4θ=0

sin4θ=sinnπ

4θ=nπ

θ=nπ/4

cos2θ=0

cos2θ=cosθ

2θ=2nπ±π/2

θ=

2

2nπ

±π/4

=nπ±

4

π

Step-by-step explanation:

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