Math, asked by moonarmy5791, 1 year ago

Sin(90-x)cos(90-x)=tanx/1+cot^2(90-x)

Answers

Answered by thesmartlerner
0

hello there mate !




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ANSWER

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rewrite sec ( 90 - x ) in terms of sins cosines

1\\___\\\\cos ( 90 -x )

sin ( 90 - x )                 - sec ( x )


mulitply    1\\    cos (90 - x) and    1\\sin ( 90 - x )






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