sin (a+b)/2=cosA/2
show the above if a,b,c are angles of a triangle
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A+B+c=180 (asp)
A+B=180-c
A+B/2=90-c/2
sin A+B/2=90-c/2==cos A/2
A+B=180-c
A+B/2=90-c/2
sin A+B/2=90-c/2==cos A/2
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