Sin(a + b)/cos(cx + d) Derive it fast
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{cos(cx + d).d/dx[sin(ax + b)] - sin(ax + b).d/dx[cos(cx + d)]}/cos²(cx + d)
{cos(cx + d).sin(ax + b).a + sin(ax + b).sin(cx + d).c}/cos²(cx + d)
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