Question

(Sin A + Cosec A)^2 + (Cos A+Sec A)^2 = 7+ tan^2 A + Cot^2 A​

Answer 1

Step-by-step explanation:

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Answer 2

» Sin²A + Cosec²A + 2sinA.cosecA + Cos²A + sec²A + 2cosA.secA ,,........(a+b)² on both

=Sin²A + cosec²A + 2×1 + cos²A +sec²A +2×1 ....(sin×cosec=1 and cos ×sec = 1)

=(sin²A +cos²A) + cosec²A + sec²A + 2+2

= 1 + (1+cot²A) + (1+ tan²A) +4 ...(sin²x + cos ²x =1 , value of cosec²x = 1 + cot²x and sec²x = 1 + tan²x)

=1+1+1+4+tan²A + cot²A

=7 + tan²A +cot²A = R.H.S