Math, asked by mogli12, 8 months ago

sin A/I-COSA + Tan A/1+cosA = cotA + SecS + Cosec A

Answers

Answered by sandy1816

Step-by-step explanation:

sinA/1-cosA+tanA/1+cosA

=sinA/1-cosA+sinA/cosA(1+cosA)

=sinAcosA(1+cosA)+sinA(1-cosA)/ cosA(1-cos²A)

=sinAcosA+sinAcos²A+sinA-sinAcosA/ cosAsin²A

=(sinAcos²A+sinA)/cosAsin²A

=sinAcos²A/cosAsin²A+sinA/cosAsin²A

=cosA/sinA+1/cosAsinA

=cotA+secA.cosecA

Previous Question

Next Question

Similar questions

Science, 4 months ago

Science, 4 months ago

English, 4 months ago

Science, 8 months ago

Hindi, 8 months ago

Math, 10 months ago

Using mathematical induction, prove that $\frac{1^{3}}{1} + \frac{1^{3} + 2^{3}}{1 + 3} + \frac{1^{3} + 2^{3} + 3^{3}}{1 + 3 + 5} + ...$ upto n terms = $\frac{n}{24} [2n^{2} + 9n + 13]$ for all n ∈ N...

Math, 10 months ago

If A = $\left[\begin{array}{ccc}-1&3\\4&2\end{array}\right]$ , B = $\left[\begin{array}{ccc}2&1\\3&-5\end{array}\right]$ , X = $\left[\begin{array}{ccc}x_{1}&x_{2}\\x_{3}&x_{4}\end{array}\right]$ and A+ B = X then find the values of x₁, x₂, x₃, and x₄.

Math, 10 months ago