Math, asked by mogli12, 1 year ago

sin A/I-COSA + Tan A/1+cosA = cotA + SecS + Cosec A

Answers

Answered by sandy1816

Step-by-step explanation:

sinA/1-cosA+tanA/1+cosA

=sinA/1-cosA+sinA/cosA(1+cosA)

=sinAcosA(1+cosA)+sinA(1-cosA)/ cosA(1-cos²A)

=sinAcosA+sinAcos²A+sinA-sinAcosA/ cosAsin²A

=(sinAcos²A+sinA)/cosAsin²A

=sinAcos²A/cosAsin²A+sinA/cosAsin²A

=cosA/sinA+1/cosAsinA

=cotA+secA.cosecA

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