Math, asked by prashant6493, 11 months ago

sin A /sec A + tan A - 1 + cos A / cosec A +cot A - 1 = 1​

Answers

Answered by sandy1816
20

Step-by-step explanation:

sinA/secA+tanA-1+cosA/cosecA+cotA-1

=sinAcosA/1+sinA-cosA+sinAcosA/1+cosA-sinA

=sinAcosA/1+(sinA-cosA) +sinAcosA/1-(sinA-cosA)

=sinAcosA{1-(sinA-cosA)}+sinAcosA{1+(sinA-cosA)}/1-(SinA-cosA)²

=2sinAcosA/2sinAcosA

=1

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Answered by nallisravankumar
3

Answer:

here is ur answer, hope this helps u

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