Question

sinα=asinβ and cosα=bcosβ then tanα=

Answer 1

Hey !!!

sinα = asinβ ©(given)
cosα = bcosβ

and we know that

tanα = sinα/cosβ

hence , from given ,

tanα = asinβ /bcosβ

tanα = a/btanβ

or , btanα = atanα . Answer

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hope it helps you !!

@Rajukumar111

Answer 2

sinα = asinβ ©(given)cosα = bcosβ 
and we know that 
tanα = sinα/cosβ
hence , from given , 
tanα = asinβ /bcosβ 
tanα = a/btanβ
or , btanα = atanα . Answer 
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hope it helps you !!