Question

sin square 60 degree + 10 square 60 degree upon sin square 30 degree + cos square 45 degree

Answer 1

I hope your question is

Sin²60° + 10 × ( Cos²60°/Sin²30° ) + Cos²45°

Solution :

Sin²60° + 10 × ( Cos²60°/Sin²30° ) + Cos²45°

= $(\frac{\sqrt{3}}{2} )^{2} + 10 * ( \frac{\frac{1}{2}}{\frac{1}{2}})^{2} + (\frac{1}{\sqrt{2}})^{2}$

= $\frac{3}{4} + 10 * 1^{2} + \frac{1}{2}$

= $\frac{3+40+2}{4}$

= $45/2 = 22.5$