sin square theta + cos square theta equal one
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heya friends.✌
As you know that...
Pythagoras theorm...
h^2=p^2+b^2---1 【let p is perpendicular b is base and h height of a right angled triangle 】
so,, As you know that .
sinQ=p/h...
and cosQ=b/h.
now from question..
sin^2Q+cos^Q
=>p^2/h^2+b^2/h^2
=>p^2+b^2/h^2
=>h^2/h^=1 【from 1)】
hope it help you..
@Rajukumar☺☺☺
As you know that...
Pythagoras theorm...
h^2=p^2+b^2---1 【let p is perpendicular b is base and h height of a right angled triangle 】
so,, As you know that .
sinQ=p/h...
and cosQ=b/h.
now from question..
sin^2Q+cos^Q
=>p^2/h^2+b^2/h^2
=>p^2+b^2/h^2
=>h^2/h^=1 【from 1)】
hope it help you..
@Rajukumar☺☺☺
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