sin (theeta) = -√3/2 .....plzz solve this question
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Sin theta=-root3/2
Sin theta=root3/2=pi/3
Sin is negative in 3rd nd fourth quadeant...
Therefore...
Third quadrant...
Sin theta=pi+pi/3
Sin theta=4pi/3
Fourth quadrant...
Sin theta=2pi-pi/3
Sin theta=5pi/3
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achha last me jo aapne likha hai ...2pi-pi/3 usko kaise solve krenge ki 5pi/3 aayega
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