Sin theta -2 sin^3 theta= (2cos^3theta-cos theta) tan theta
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sinQ-2sin³Q = (2cos³Q-cosQ) tanQ
==> sinQ-2sin³Q/2cos³Q-cosQ = tan Q
==> sinQ(1-2 sin²Q) / cos (2 cos²Q-1) = tan Q
==> sinQ(1-2(1-cos²Q) / cosQ (2 cos²Q-1) = tan Q
==> sinQ(1-2+2cos²Q) / cosQ (2 cos²Q-1) = tan Q
==> sinQ(2cos²Q-1) / cosQ (2 cos²Q-1) = tan Q
==> sinQ/cosQ = tan Q
==> tan Q = tan Q
I HOPE ITS HELPFUL
==> sinQ-2sin³Q/2cos³Q-cosQ = tan Q
==> sinQ(1-2 sin²Q) / cos (2 cos²Q-1) = tan Q
==> sinQ(1-2(1-cos²Q) / cosQ (2 cos²Q-1) = tan Q
==> sinQ(1-2+2cos²Q) / cosQ (2 cos²Q-1) = tan Q
==> sinQ(2cos²Q-1) / cosQ (2 cos²Q-1) = tan Q
==> sinQ/cosQ = tan Q
==> tan Q = tan Q
I HOPE ITS HELPFUL
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