sin theta + 2cos theta =2 then (cos theta -2sin theta) is
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If cos theta + sec theta = 2 what is the value of cos^100 theta +sec^100 theta?
Cos theta+sec theta =2
=> cos ^2 theta +1 = 2 cos theta
=> cos^2 theta -2 cos theta +1=0
Solving the above quadratic equation in cos theta,we get
cos theta =1
=>theta =cos inverse (1)
=>theta=2 n pi
Now we need to find the value of
cos 100 theta+sec 100 theta
Substitute the value of theta as theta=2 n pi:
=>cos 100 theta + sec 100 theta = cos 100 (2 n pi) + sec 100 (2 n pi)
=cos 2 (100n pi) + sec 2 (100n pi)
Let 100n=k , some variable
=>cos 100 theta + sec 100 theta = cos (2 k pi) + sec (2 k pi) = 1 + 1 = 2
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