sin (x + y) = cos [3(x+y)], तो tan [2(x+y)] का मान कितना होगा?; sin(x + y) = cos[3(x + y)]; ⇒ sin(x + y) = sin[90° – (3x + 3y)]; [चूँकि, sin(90° – θ) = cos θ]; ⇒ x + y = 90° – 3x – 3y; ⇒ 4x + 4y = 90°; ⇒ 2x + 2y = 45°; ∴ tan(2x + 2y) = tan 45° = 1
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Answer:
b.1
Step-by-step explanation:
sin (x+y)= cos[3(x+y)]
=>sin(x+y)=sin [90-(3x+3y)]
=>x+y =90-3x-3y
=>4x+4y=90
=>2x+2y=45
=>2(x+y)=45
Therefore,tan 2(x+y) = tan 45=1
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