Math, asked by AyushSignhh3388, 1 year ago

sin (x + y) = cos [3(x+y)], तो tan [2(x+y)] का मान कितना होगा?; sin(x + y) = cos[3(x + y)]; ⇒ sin(x + y) = sin[90° – (3x + 3y)]; [चूँकि, sin(90° – θ) = cos θ]; ⇒ x + y = 90° – 3x – 3y; ⇒ 4x + 4y = 90°; ⇒ 2x + 2y = 45°; ∴ tan(2x + 2y) = tan 45° = 1
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B. 1
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Answers

Answered by ddduroydutta
0

Answer:

b.1

Step-by-step explanation:

sin (x+y)= cos[3(x+y)]

=>sin(x+y)=sin [90-(3x+3y)]

=>x+y =90-3x-3y

=>4x+4y=90

=>2x+2y=45

=>2(x+y)=45

Therefore,tan 2(x+y) = tan 45=1

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