Math, asked by goutham11111111111, 1 year ago

sin15° sec75°=??? evalute this,urgent.

Answers

Answered by adityakjha24
4
sin15° sec75°


sin15°. Sec (90-15)

Sin15. Cosec15 ....... [ Sec(90-A) ~ cosecA ]

Sin15.(1/sin15) .......[ cosec A ~ 1/sinA]

1



Hope it helps
Answered by throwdolbeau
4

Answer:

The solution of sin 15° sec 75° is equal to 1  

Step-by-step explanation:

Solve : sin 15° sec 75°  

Solution :  

\sec\theta=\frac{1}{\cos\theta}\\\\\implies\sec 75=\frac{1}{\cos 75}

\sin 15\cdot \sec 75\\\\\implies \sin 15\cdot \frac{1}{\cos 75}\\\\\implies \sin 15\times \frac{1}{\cos(90-15)}\\\\\implies \sin 15\times \frac{1}{\sin 15}\\\\\implies 1

Therefore, The solution of sin 15° sec 75° is equal to 1

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