Question

sin2A=2sinAcosA then sinA=??​

Answer 1

Answer:

SinA = SinA/2CosA/2

Step-by-step explanation:

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Answer 2

Answer

$\mathsf{sinA= 2 \: sin \dfrac{A}{2} \: cos \dfrac{A}{2}}$

Explanation:-

Given

$\mathsf{sin \:2A = 2 \: sinA \: cosA}$

To Find

sinA

Solution

We have

$\mathsf{sin \:2A = 2 \: sinA \: cosA}$

Let's divide, the angles by "2"

$\mathsf{sin \: \dfrac{2A}{2} = 2 \: sin \dfrac{A}{2} \: cos \dfrac{A}{2}}$

$\mathsf{sinA= 2 \: sin \dfrac{A}{2} \: cos \dfrac{A}{2}}$

Hence,

$\huge \star$$\red{\boxed{\blue{\mathsf{sinA= 2 \: sin \dfrac{A}{2} \: cos \dfrac{A}{2}}}}}$