Question

Sin2A=cos (A-36°),2A and A-26° are acute angle then find the value of A

Answer 1

sin2A=cos(A-36)

sin2A=sin[90-(A-36)]

2A=126-A                            [Sin cancelled sin]

3A=126

A=126/3

A=42

Answer 2

Answer:

ANSWER IS 42

Step-by-step explanation:

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