sin2A+sin2B-sin2C=-4sinAsinBcosC
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If A+B+C=180 degree, then A+B=180-C hence sin(A+B) = sinC, cos(A+B)=-cosC
sin2A + sin 2B +sin2C
= 2 sin(A+B)cos(A-B) + 2sinC cosC
=2sinC cos(A-B)+2sinC cosC
=2sinC (cos(A-b) + cos C)
=2sin C(cos(A-B) - cos(A+B) )
= 2sinC . 2sin A sin B
=4 sinA sin B sin C
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