Question

sin2x.cotx =2-2sin²x​

Answer 1

Consider LHS = Sin2x . Cotx

= ( 2 Sinx Cosx ) . ( Cosx / Sinx )

Since Sib2@ = 2 Sin@ Cos@

= ( 2 × Sinx × Cosx × Cosx ) / Sinx

= 2 Cos^2 ( x )

= 2 ( 1 - Sin^2x )

( since , Cos^2x = 1 - Sin^2x )

= 2 - 2 Sin^2x

= RHS