Question

Sin3A=cos(A-B) then find angleA=?

Answer 1

Answer:a=(90+b)/4

Step-by-step explanation:

sin3a=cos(a-b)

sin3a=sin(90-(a-b)),    since sinx=cos(90-x)

sin3a=sin(90-a+b)

comparing both sides

3a=90-a+b

4a=90+b

a=(90+b)/4

Answer 2

Answer:

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#Here's ur answer...☆☆☆

Step-by-step explanation:

$\sin(3a) = \cos(a - b) \\ = > \cos(90 - 3a) = \cos(a - b) \\ = > 90 - 3a = a - b \\ = > 90 + b = 4a \\ = > a = \frac{90 + b}{4}$

Hope this helps you...✌✌

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