Question

sin48 sin42 + cos48 cosec 42= 2​

Answer 1

Step-by-step explanation:

$\sin(48 ) \sin(42) + \cos(48) \csc(42) = 2$

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Answer 2

Answer:

THE QUESTION IS WRONG IT CAN'T BE =2

THE REAL QUESTION SHOULD BE

sin48 sec42 + cos48 cosec 42= 2

sin48=sin(90-42)

=cos42

cos48=cos(90-42)

=sin42

substituting the value

(cos42×sec42)+(sin48×cosec48)

=1+1 (since cosa×seca=1,sina×coseca=1)

=2

hence proved

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