Math, asked by piyush1219, 1 year ago

sinA÷1-cosA=secA+cotA

Answers

Answered by shivakumarah

2

sinA÷1-cosA

=sinA÷1-cosA ×1+cosA÷1+cosA

=sinA+sinA cosA÷1+cos2(A)

=secA+cotA

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