Math, asked by vikram15379488, 9 months ago

sinA/1-cosA+tanA/1+cosA=secA.cosecA.cotA​

Answers

Answered by Darvince
5

Step-by-step explanation:

L.H.S

=Sin A(1+cos A+tan Afl- cos Y/1- cos^2 A

Sin A + Sin A. cos A +tan A-tan A.cos A/sin^ 2 A

Sin A +Sin A. Cos A+tan A - sinA /Cos A + COS A/

sin ^2 A

Sin A +Sin A.cos A + tan A-Sin A/Sin^ 2 A

Sin A. cos A +sin A/Cos A/sin ^2 A

Sin A(Cos^2 A +1/cos A)/ Sin^2 A

Cos^2 A+1/cos A sina

Cos ^2 A/cos A. SinA +1/cos A. sinA

cos A/Sin A +Sec A. Cosec A= Cot A + Sec

A.Cosec A

Answered by basavaraj5392
1

Attached above, hope you satisfied with my answer.

please mark as brainly.

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