) The sum of the sides of two squares is 80 meters. Also the sum of the areas of these
two squares is 3400 square meters. Find the side of each square. Also find the
difference between the perimeters of these squares
Answers
Sides of Square are 50 m & 30 m , difference between the perimeters of these squares = 80 m
Step-by-step explanation:
Let say two square with sides A & B
Sum of the sides of two square = A + B = 80
=> A + B = 80
Squaring both Sides
=> A² + B² + 2AB = 6400
sum of the areas of these two squares is 3400m²
=> A² + B² = 3400
=> 3400 + 2AB = 6400
=> 2AB = 3000
A² + B² + 2AB = 6400
=> A² + B² - 2AB = 6400 - 4AB
=> (A - B)²= 6400 - 6000
=> (A - B)² = 400
=> A - B = 20
A + B = 80
=> 2A = 100
& A = 50 , B = 30
Sides of Square are 50 m & 30 m
difference between the perimeters of these squares = 4(50) - 4(30)
= 80 m
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