Question

sina(1+tana)+cosa(1+cota)=seca+coseca​

Answer 1

Answer:

Step-by-step explanation:

LHS:

sina(1+tana)+cosa(1+cota)

sina+sina*tana+cosa+cosa*cota

sina+sina*sina/cosa+cosa+cosa*cosa/sina

=sina+sin^2a/cosa+cosa+cos^2a/sina

=sina+cosa+sin^2a/cosa+cos^2a/sina

=(sin^2acosa+cos^2asina+sin^3a+cos^3a)/sina*cosa

=(sin^2cosa+sin^3a+cons^2asina+cos^3a)/sinacosa

=((1-cos^a)cosa+sin^3a+(1-sin^a)sina+cos^3a)/sinacosa

=cosa-cos^3a+sin^3a+sina-sin^3a+con^3a)/sinacosa

=sina+cosa)/sinacoas

=sina/sinacoas+cosa/cosa*sina=1/cosa+1/sina=coseca+seca=RHS