sinA-cosA=0 then find sin4A+cos4A
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Answer:
Step-by-step explanation:
sinA-cosA=0
sinA=cosA
A=45°
sin4A+cos4A=sin4*45°+cos*45°
sin180+cos180=sin (90° + 90°) +cos (90° + 90°) {sin (90° + θ) = cos θ,cos (90° + θ) = - sin θ}
= cos90°-sin90°
0-1=-1
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