Math, asked by sanketsherikar313, 11 months ago

sinA-cosA=0 then find sin4A+cos4A​

Answers

Answered by Suyash4112003
3

Answer:

Step-by-step explanation:

sinA-cosA=0

sinA=cosA

A=45°

sin4A+cos4A=sin4*45°+cos*45°

sin180+cos180=sin (90° + 90°) +cos (90° + 90°) {sin (90° + θ) = cos θ,cos (90° + θ) = - sin θ}

= cos90°-sin90°

0-1=-1

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