Question

sina÷sin(90-a)+ cosa÷cos(90-a) =secacoseca​

Answer 1

Solution:

_________________

Here ,we are using

i) sin(90-A) = cosA

ii) cos(90-A) = sinA

iii) sin²A+cos²A = 1

iv) 1/sinA = cosecA

v) 1/cosA = secA

________________

LHS = sinA/sin(90-A)+cosA/cos(90-A)

= sinA/cosA + cosA/sinA

= (sin²A + cos²A)/(sinAcosA)

= 1/(sinAcosA)

= cosecAsecA

= secAcosecA

= RHS

••••

Answer 2

Hey!

Refer the below attachment !

Thanks !