Question

sinasin(a+2b)-sinbsin(b+2a)=sin(a+b)sin(a-b)​

Answer 1

Answer:

½ [cos (- 2B ) – cos (2A + 2B) – cos(- 2A) + cos (cos 2A + 2B)]

½ [cos 2B – cos 2A]

½ [2 sin^2 A – 2 sin^2 B]

sin^2 A – sin^2B

sin (A + B) sin(A – B)

Step-by-step explanation:

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