Question

sinx
+ cosec n =2 Find sinn +cosecnx​

Answer 1

Answer:

Step-by-step explanation:

sin x + cosec x = 2

sin x + (1/sin x) = 2

(sin2x + 1)/sin x = 2

sin2x + 1 = 2 sin x

sin2x – 2 sin x + 1 = 0

(sin x – 1)2 = 0

sin x – 1 = 0

sin x = 1

cosec x = 1/sin x = 1

sinnx + cosecnx = (1)n + (1)n

= 1 + 1

= 2

here x is n ok pls mark me as brainliest