Question

Six year hence ,a man,s age will be 3 time's his sons age and three years ago he was nine times as old as his son find their present age

Answer 1

Hiii friend....☺

Let the present age of man be X and the age of his son Be Y years.

After 6 years age of man = (X+6) years.

After 6 years age of son = (Y+6) years.

According to question,

X +6 = 3(Y+6)

X + 6 = 3Y +18

X -3Y = 18 -6

X -3Y = 12......(1)

Again,

Before 3 years age of father = (X-3) years.

Before 3 years age of son = (Y-3) years.

According to question,

X -3 = 9(Y-3)

X-3 = 9Y -27

X -9Y = -27+3

X -9Y = -24.......(2)


From equation (1) we get,

X -3Y = 12

X = 12+3Y.......(3)

Putting the value of X in equation (2)

X -9Y = -24

12+3Y -9Y = -24

-6Y = -24-12

-6Y = -36

Y = 36/6 = 6 years

Putting the value of Y in equation (3)

X = 12+3Y => 12 + 3 × 6 = 12+18 = 30 years.

Age of son = Y = 6 years

and,

Age of father = X = 30 years.


HOPE IT WILL HELP YOU.....☺