Six years ago ,the age of mother was equal to the square of her son's ahe . After three years ,her age will be thrice the age of her son then find the present age of mother and son
Answers
Answer:
Son = 12 years
Mother = 42 years
Explanation -
Six years ago let the son age = x
Mother = x²
Present ages now:
Son = x + 6
Mother = x² + 6
3 years later:
Son = x + 6 + 3 = x + 9
Mother = x² + 6 + 3 = x² + 9
Solving x -
x² + 9 = 3(x + 9)
x² + 9 = 3x + 27
x² - 3x - 18 = 0
(x - 6)(x + 3) = 0
x = 6 or x = -3
Take x = 6. As the other value is (- value)
Finding their Present age -
Son = x + 6 = 6 + 6 = 12 years.
Mother = x² + 6 = (6)² + 6 = 42 years.
Hence :
Son = 12 years
Mother = 42 years
Answer:
Son = 12 years
Mother = 42 years
Explanation -
Six years ago let the son age = x
Mother = x²
Present ages now:
Son = x + 6
Mother = x² + 6
3 years later:
Son = x + 6 + 3 = x + 9
Mother = x² + 6 + 3 = x² + 9
Solving x -
x² + 9 = 3(x + 9)
x² + 9 = 3x + 27
x² - 3x - 18 = 0
(x - 6)(x + 3) = 0
x = 6 or x = -3
Take x = 6. As the other value is (- value)
Finding their Present age -
Son = x + 6 = 6 + 6 = 12 years.
Mother = x² + 6 = (6)² + 6 = 42 years.
Hence :
Son = 12 years
Mother = 42 years
Plz mark brainliest