slove using identity (98)3
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Answered by
5
98^3
= (100 - 2) ^3
[ (a-b) ^3 = a^3 - b^3 - 3ab(a - b)]
= (100)^3 - (2)^3 - 3(100)(2)( 98)
= 1000000 - 8 - ( 600 × 98)
= 1000000 - 8 - 58800
= 999992 - 58800
= 941192
= (100 - 2) ^3
[ (a-b) ^3 = a^3 - b^3 - 3ab(a - b)]
= (100)^3 - (2)^3 - 3(100)(2)( 98)
= 1000000 - 8 - ( 600 × 98)
= 1000000 - 8 - 58800
= 999992 - 58800
= 941192
Kafila:
thanks one more time
Answered by
4
Hola there,
=> (98)³
=> (100 - 2)³
We know : (a - b)³ = a³ - b³ - 3ab(a - b)
So,
=> (100)³ - (2)³ - 3(100)(2)(100 - 2)
=> 1000000 - 8 - 600(98)
=> 1000000 - 58808
=> 941192. ....Ans
Hope this helps...:)
=> (98)³
=> (100 - 2)³
We know : (a - b)³ = a³ - b³ - 3ab(a - b)
So,
=> (100)³ - (2)³ - 3(100)(2)(100 - 2)
=> 1000000 - 8 - 600(98)
=> 1000000 - 58808
=> 941192. ....Ans
Hope this helps...:)
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