smallest number divisible by 15,20,24,32,36
Answers
Answered by
41
the smallest no. divisible by any two or more numbers is the L.C.M. of all those numbers.
therefore, taking the LCM of 15,20,24,32,and 36
2*2*2*2*2*3*3*5*5= 7200
so 7200 is the required number.
therefore, taking the LCM of 15,20,24,32,and 36
2*2*2*2*2*3*3*5*5= 7200
so 7200 is the required number.
JaswinderBehl:
lcm of 15,20,24,32,36 is 2*2*3*2*5*4*3=1440 and 1440 is divisible by all
Answered by
25
Lowest common multiple of 15, 20, 24, 32, 36 is 1440.
To find:
“Smallest number” divisible by 15, 20, 24, 32, 36.
Solution:
To find the least number divisible by ‘15, 20, 24, 32 & 36’, we have to find L.C.M. of the given numbers.
The “smallest positive number” that is a “multiple of two or more numbers”.
L.C.M of ‘15, 20, 24, 32 & 36’ is derived in below attached image.
Hence, L.C.M. .
Attachments:
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