smallest number divisible by 15,20,24,32,36
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Answered by
41
the smallest no. divisible by any two or more numbers is the L.C.M. of all those numbers.
therefore, taking the LCM of 15,20,24,32,and 36
2*2*2*2*2*3*3*5*5= 7200
so 7200 is the required number.
therefore, taking the LCM of 15,20,24,32,and 36
2*2*2*2*2*3*3*5*5= 7200
so 7200 is the required number.
JaswinderBehl:
lcm of 15,20,24,32,36 is 2*2*3*2*5*4*3=1440 and 1440 is divisible by all
Answered by
25
Lowest common multiple of 15, 20, 24, 32, 36 is 1440.
To find:
“Smallest number” divisible by 15, 20, 24, 32, 36.
Solution:
To find the least number divisible by ‘15, 20, 24, 32 & 36’, we have to find L.C.M. of the given numbers.
The “smallest positive number” that is a “multiple of two or more numbers”.
L.C.M of ‘15, 20, 24, 32 & 36’ is derived in below attached image.
Hence, L.C.M. .
Attachments:
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