Question

Sodium bi carbonate breaks down on heating: 2NaHCO3 Na2 CO3 + H2O + CO2 (Atomic mass of Na = 23, C = 12, H = 1, O=16) i) How many moles of sodium bi carbonate are there in the equation? ii) What is the mass of sodium bicarbonate used in this equation? iii) How many moles of carbon dioxide are there in this equation?

Answer 1

The given balanced reaction is as follows.

2 NaH〖CO〗_3   → 〖Na〗_2 〖CO〗_3+ H_2 O+ 〖CO〗_2

This equation shows that Sodium bicarbonate decomposes to Sodium carbonate, water and carbon dioxide gas.

From given: Atomic mass of Na =23 g/mol

                     Atomic mass of C = 12 g/mol

                     Atomic mass of O = 16 g/mol

In the reaction 2 moles of sodium carbonate involved

Mass of sodium bicarbonate = 2(23+1+12+3(16))

                                                   = 168 g/mol

One mole of carbondioxide is produced.