Question

Sodium metal crystallizes in bcc structure with the edge length of the unit cell 4.3×10^-8 cm calculate the radius of sodium atom

Answer 1

Answer: refer the material.

Explanation:

Answer 2

Answer:

$Radius=1.86\ \dot{A}$

Explanation:

In a BCC lattice, the atoms are arranged as that the atoms are at the corners and 1 atom in the center of the lattice. Thus, along the diagonal atoms are touched together.

Thus,

$4\times radius=\sqrt 3\times edge\length$

Given :

$Edge\ length=4.3\times 10^{-8}\ cm$

Also, $1\ cm=10^{-8}\ \dot{A}$

So,

$Edge\ length=4.3\ \dot{A}$

Thus,

$4\times radius=\sqrt 3\times 4.3\ \dot{A}$

$Radius=1.86\ \dot{A}$