Math, asked by jatsheeshram8, 10 months ago

Solue √3
is irrational​

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Answered by KJB811217
5

Answer:

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Answered by xBrainlyKingXx
2

Answer:

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We assume √3 is a rational number

i.e. √3=a/b v(where a and b are coprime and b≠0

√3b=a

3b^2=a^2

therefore 3divides a^2

which implies 3 divides a

Put. a=3c

3b^2=9c^2

b^2=3c^2

therefore 3 divides b^2

which implies 3 divides b

it is a contradiction to our fact that a and be are coprime

therefore our assumption is wrong

which implies that √3 is an irrational no.( 1)

we assume 2√3+5 is a rational number

i.e. 2√3+5=p/q (where p and q are coprime and b≠0)

√3=p-5q/2q

which is a rational number

it is a contradiction to our fact that √3 is an irrational no.

therefore our assumption is wrong

which implies that 2√3+5 is an irrational no.

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