Question

solution of this question❓
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Answer 1

Answer:

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Answer 2

Answer:solved below

Step-by-step explanation:

Given tanA=(1/√3)=p/b

Now h^2=p^2+b^2

=1+3=4

Therefore h=2

Now SinA=1/2 and SinC=√3/2

CosA=√3/2 and CosC=1/2

Now question (I)

SinACosC+CosASinC

=(1/2)(1/2)+(√3/2)(√3/2)

=(1/4)+(3/4)= 4/4=1

Similarly solve the second one.

Hope it helps you.