solution this question,find the shaded area correct to 1d.p.(use 3.14 for pi).
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Q.8=10×14-1/2πr^2
Q.9=2πR1^2-2πR2^2
Q.10=(5)^2-2πr^2
Q.9=2πR1^2-2πR2^2
Q.10=(5)^2-2πr^2
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