solve 11a) please I want the answer
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First of all,
2 integer 1/2 = 5/2
1 integer 2/3 = 5/3
1 integer 3/4 = 7/4
Let the three parts of 4260 be 5x/2, 5x/3 and 7x/4
So, 5x/2 + 5x/3 + 7x/4 = 4260
LCM = 12 (Multiplying 12 on both sides)
∴ 5x/2 * 12 + 5x/3 * 12 + 7x/4 * 12 = 4260 * 12
∴5x * 6 + 5x * 4 + 7x * 3 = 51120
∴30x + 20x + 21x = 51120
∴71x = 51120
∴x = 720
So, the first part = 5x/2 = 5*720/2 = 5*360 = Rs. 1800
The second part = 5x/3 = 5*720/3 = 5*240 = Rs. 1200
The third part = 7x/4 = 7*720/4 = 7*180 = Rs. 1260
Thus, the three parts of Rs. 4260 in required proportions are Rs. 1800, Rs. 1200 and Rs. 1260 respectively.
2 integer 1/2 = 5/2
1 integer 2/3 = 5/3
1 integer 3/4 = 7/4
Let the three parts of 4260 be 5x/2, 5x/3 and 7x/4
So, 5x/2 + 5x/3 + 7x/4 = 4260
LCM = 12 (Multiplying 12 on both sides)
∴ 5x/2 * 12 + 5x/3 * 12 + 7x/4 * 12 = 4260 * 12
∴5x * 6 + 5x * 4 + 7x * 3 = 51120
∴30x + 20x + 21x = 51120
∴71x = 51120
∴x = 720
So, the first part = 5x/2 = 5*720/2 = 5*360 = Rs. 1800
The second part = 5x/3 = 5*720/3 = 5*240 = Rs. 1200
The third part = 7x/4 = 7*720/4 = 7*180 = Rs. 1260
Thus, the three parts of Rs. 4260 in required proportions are Rs. 1800, Rs. 1200 and Rs. 1260 respectively.
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your welcome come can you solve my more doubts please
I will try. Where can I find them?
I posted two questions please solve it
The other one, its already solved; Should I do it again?
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