Math, asked by priyanshidoshi693, 1 month ago

Solve 2/3(4x-1)-(4x-1-3x/2)=x-7 and verify answer

Answers

Answered by raghulragavi07
0

Step-by-step explanation:

Solution for 2/3(4x-1)-(4x-1-3x/2)=x-7/2 equation:

x in (-oo:+oo)

(2/3)*(4*x-1)-(4*x)+(3*x)/2+1 = x-(7/2) // - x-(7/2)

(2/3)*(4*x-1)-(4*x)+(3*x)/2-x+7/2+1 = 0

(2/3)*(4*x-1)-4*x+(3*x)/2-x+7/2+1 = 0

2/3*(4*x-1)-4*x+(3*x)/2-x+7/2+1 = 0

(2/3*2*(4*x-1))/2+(-4*2*x)/2+(3*x)/2+(2*(-x))/2+7/2+(1*2)/2 = 0

2/3*2*(4*x-1)-4*2*x+3*x+2*(-x)+1*2+7 = 0

3*x-8/3*x-2*x-4/3+2+7 = 0

1/3*x-2*x-4/3+2+7 = 0

2-5/3*x-4/3+7 = 0

2-5/3*x+17/3 = 0

23/3-5/3*x = 0

(23/3-5/3*x)/2 = 0

(23/3-5/3*x)/2 = 0 // * 2

23/3-5/3*x = 0

23/3-5/3*x = 0 // - 23/3

-5/3*x = -23/3 // : -5/3

x = -23/3/(-5/3)

x = 23/5

x = 23/5

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