Question

solve: (2 root 3 +3 root 2) (2 root 6 -3 root 10)
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Answer 1

$\huge{\underline{\color{pink}{\mathfrak{Answer}}}}$

= (2 √3 + 3√2 ) ( 2√6 - 3√10 )

$=4\sqrt{6}\sqrt{3}-6\sqrt{10}\sqrt{3}+6\sqrt{2}\sqrt{6}-9\sqrt{2}\sqrt{10}\approx -35.357404606$

$=4\sqrt{3}\sqrt{2}\sqrt{3}-6\sqrt{10}\sqrt{3}+6\sqrt{2}\sqrt{6}-9\sqrt{2}\sqrt{10}\approx -35.357404606$

$=4\times 3\sqrt{2}-6\sqrt{10}\sqrt{3}+6\sqrt{2}\sqrt{6}-9\sqrt{2}\sqrt{10}\approx -35.357404606$

$=12\sqrt{2}-6\sqrt{10}\sqrt{3}+6\sqrt{2}\sqrt{6}-9\sqrt{2}\sqrt{10}\approx -35.357404606$

$=12\sqrt{2}-6\sqrt{30}+6\sqrt{2}\sqrt{6}-9\sqrt{2}\sqrt{10}\approx -35.357404606$

$=12\sqrt{2}-6\sqrt{30}+6\sqrt{2}\sqrt{2}\sqrt{3}-9\sqrt{2}\sqrt{10}\approx -35.357404606$

$=12\sqrt{2}-6\sqrt{30}+6\times 2\sqrt{3}-9\sqrt{2}\sqrt{10}\approx -35.357404606$

$=12\sqrt{2}-6\sqrt{30}+12\sqrt{3}-9\sqrt{2}\sqrt{10}\approx -35.357404606$

$=12\sqrt{2}-6\sqrt{30}+12\sqrt{3}-9\sqrt{2}\sqrt{2}\sqrt{5}\approx -35.357404606$

$=12\sqrt{2}-6\sqrt{30}+12\sqrt{3}-9\times 2\sqrt{5}\approx -35.357404606$

$=12\sqrt{2}-6\sqrt{30}+12\sqrt{3}-18\sqrt{5}\approx -35.357404606$

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