Question

solve 2/x+2/3y = 1/6 ; 3/x+2/y=0 and hence find 'a' for which y=ax-4

Answer 1

Answer:

Taking  

x

1

​

=u and  

y

1

​

=v. The given system of equations become

2u+  

3

2

​

v=  

6

1

​

 

⇒12u+4v=1   (i)

and, 3u+2v=0 .(ii)

Multiplying equation (ii) by 2 and subtracting from equation (i), we get

6u−1⇒u=  

6

1

​

 

Putting u=  

6

1

​

 in (i), we get

2+4v=1⇒v=−  

4

1

​

 

Hence, x=  

u

1

​

=6 and y=  

v

1

​

=−4

So, the solution of the given system of equations is x=6,y=−4

Putting x=6,y=−4 in y=ax−4, we get

−4=6a−4⇒a=0.

Step-by-step explanation:

thank you