Question

Solve 2/x+2/3y/=1/6,3/x+2/y=0 by substituting

Answer 1

Step-by-step explanation:

let 1/x=a;1/y=b

=>2a+2b/3 = 1/6=>(take lcm)6a+2b = 3/6=1/2

3a+2b = 0

the equations are,

=>6a+2b = 1/2 = 12a+4b = 1_________(1)

=>3a+2b = 0_________________________(2)

from (2),

a=-2b/3___________________(3)

subs (3) in (1)

=>12 (-2b/3)+4b = 1

=>-8b+4b =1

=>-4b = 1

=>b = -1/4

subs b = -1/4 in (3)

a=-2 (-1/4)/3

=>2/4/3

=>2/12

=>a=1/6

1/x = a = 1/6 => x = 6

1/y = b = -1/4=>y= -4