Question

Solve: 2/y+3/x =7/xy ; 6/y+9/x=11/xy

Answer 1

Hi mate. Here is your answer

2/y+3/x=7/xy. => 6/y+9/x=11/xy
=> 2x+3y/xy=7/xy. => 6x+9y/xy =11/xy
=>2x+3y=7 (let 1) => 6x+9y=11 (let 2)

From 1 and 2 we get
2x+3y =7 - - - - (1 )× 3
6x+3y=11 - - - - (2 )× 1

Now, 6x+18y=21
6x+3y=11
(-) (-) (-)
_________
15y=10
y= 10/15 = 2/3

Putting y=2/3 in equation 1 we get,

2x+3y=7
2x+3(2/3)=7
2x+2=7
x=7-2/2=5/2

Ans) X=5/2 and Y=2/3

HOPE YOU GET YOUR ANSWER!!

Answer 2

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$\huge\bold{Question:-}$

Solve: 2/y+3/x =7/xy ; 6/y+9/x=11/xy?

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$\huge\bold{Answer:-}$

Prefer the above attachment! (:

There’s a pattern between the two equations: the numerators in the first two terms are products of the numerators in the first equation and the number 3. The problem is that the numerator of the term on the opposite side of the equation is not multiplied by 3. If it were, it would look like this:

6/y + 9/x = 21/xy

Because all three terms are not of the same proportion there are no solutions to this system of equations. They each describe their terms differently so they cannot share any terms (which is what happens in a system of equations). Thus, these equations are not of the same system!

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