Question

SOLVE 25x² + 53x - 7 = 0

Answer 1

Answer:

x = -b +/-

$- b + - \sqrt{b {}^{2} } - 4ac$

Answer 2

Step-by-step explanation:

25x² + 53x - 7 = 0

Compare the above equation with the ax² + bx + c = 0

We get,

a = 25

b = 53

c = -7

So,

According to Sreedhar Achariya's formula

$x = \frac{ - b \binom{ + }{ - } \sqrt{{b} ^{2} - 4ac} }{2a}$

Putting the value of a, b, and c

We get,

$x = \frac{ - 53 \binom{ + }{ - } \sqrt{ {53}^{2} - 4 \times 25 \times ( - 7) }}{2 \times 25} \\ = \frac{ - 53 \binom{ + }{ - } \sqrt{2809 + 700}}{50} \\ = \frac{ - 53 \binom{ + }{ - } \sqrt{3509} }{50} \\ = \frac{ - 53 \binom{ + }{ - }59.24 }{50} \\ x = \frac{ - 53 + 59.24}{50} \: \: or \: \: \frac{ - 53 - 59.24}{50} \\ x = \frac{6.24}{50} \: \: \: or \: \: \frac{ - 112.24}{50} \\ x = 0.125 \: \: \: or \: \: 2.245$

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