Math, asked by kushal3865, 10 months ago

Solve : 2xsquare - 2√x + 1 = 0​

Answers

Answered by shreekant16
0

Answer:

1/4

Step-by-step explanation:

suppose

 \sqrt{x}

= y

then,

2y^2 - 2y +1 =0

y^2 + y^2 - 2y +1 =0

y^2 + (y-1)^2 = 0

y^2 = - (y-1)^2

y = -y + 1

(-y +1)/y = 1

-1 + 1/y = 1

1/y = 2

y = 1/2

x = y^2 = 1/4

Answered by Anisha5119
7

Answer:

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