Solve : 2xsquare - 2√x + 1 = 0
Answers
Answered by
0
Answer:
1/4
Step-by-step explanation:
suppose
= y
then,
2y^2 - 2y +1 =0
y^2 + y^2 - 2y +1 =0
y^2 + (y-1)^2 = 0
y^2 = - (y-1)^2
y = -y + 1
(-y +1)/y = 1
-1 + 1/y = 1
1/y = 2
y = 1/2
x = y^2 = 1/4
Answered by
7
Answer:
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